Question

(d/dx)[(x+8)/(x^2+x+2)]=

Answer 1

quotient rule again

[(x+8)'(x^2+x+2)-(x+8)(x^2+x+2)']/(x^2 + x + 2)^2

[1(x^2+x+2) -(x+8)(2x+1)]/(x^2+x+2)^2

[x^2 + x + 2 - 2x^2 - 17x - 8]/(x^2 + x + 2)^2

(-x^2 - 16x - 6) / (x^2 + x +2 )^2