Question

algebra 1b
solve by factoring

3x squared + 7x-6=0

Answer 1

(3x - 2) (x + 2) = 0

Answer 2

i mean (3x-2) ( x + 3)

Answer 3

\[3x ^{2}+7x-6\]

Answer 4

x=2/3 and -3

Answer 5

how do you get that. i really need to understand

Answer 6

trial and error
you can also use quadratic equation

Answer 7

3x^2 + 7x-6=0

3x^2 + 9x-2x-6=0

3x(x+3)-2(x+3)=0

(x+3)(3x-2)=0

Answer 8

\[step 1. (x+9)(x-2) step 2??\]

Answer 9

(x+3)(3x-2)=0

(x+3) = 0 and 3x-2 = 0

x = -3 and x = 2/3

Answer 10

how did you get
(x+3)(3x-2) ????

Answer 11

from this line 3x(x+3)-2(x+3)=0

if u factorise (x+3) , u may get

Answer 12

correction:
how did you get \[3x ^{2}+7x-6=0\]

Answer 13

sorry im confusing myself .

Answer 14

my teacher makes us do a big x.
so what multiplies to -12 and adds to 7.
i got 9 and -2
so (x+9) (x-2)
how do i go on from there

Answer 15

can u type your question again with mathematical symbols ?

Answer 16

solve by factoring
\[3x ^{2}+7x-6=0\]

step one. FACTOR.

multiply -6 and 3
to get -18.
now find what multiplies to -18
make sure that they also add to get 7.
9 and -2 MULTIPLY together and make -18
and ADD to make 7.
so you make the equation
(x+9)(x-2)=0
but you still have to do more for the rest of the problem.
so im confused on the rest

Answer 17

substitute your -9 and 2 for 7

Answer 18

sorry 9 and -2

Answer 19

so it would be
\[3x ^{2}+(x+9)(x-2)-6=0 ?\] that makes no sense

Answer 20

no, \[3x^2 +9x - 2x -6=0\]

Answer 21

so what do i do to solve that? add like terms?

Answer 22

then,. factorise 3x from from 1st two terms ans factorise 2 from last two terms

Answer 23

3x(x+3) -2(x+3)

Answer 24

yes, then factorise (x+3)

Answer 25

wait so how to i solve the rest of the problem

Answer 26

then, each of them equal to zero

Answer 27

3x(x+3)=0 -2(x+3)=0

Answer 28

no, when u factorise by ( x-3), u will get (x-3)(3x-2) = 0

Answer 29

After that make, x-3 = 0 and 3x- 2 = 0

Answer 30

howd you get (x-3) and (3x-2)

Answer 31

from 3x(x+3) -2(x+3) = 0, factorise (x+3)

Answer 32

take out x+3 , then 3x-2 is other balance

Answer 33

how do you get 3x-2

Answer 34

from 3x(x+3) -2(x+3), take out x-3, from 1st term 3x and 2nd term -2 is balance

Answer 35

because (x+3)(x+3) cancel out. leaving ONE (x+3) and whats left is 3x-2?

Answer 36

3x(x+3) -2(x+3)

if u see front of (x+3),there is 3x and -2.

Answer 37

3x-2=0
x-2=0/3
x=3/1+2/1
x=6

x+3=0
x= -3

x= 3 x= 6

Answer 38

nope,



3x-2 = 0 and x+3=0
3x=2 x=-3
x=3/2

Answer 39

not x=2/3 ???

Answer 40

x = 2/3 is correct, if u substitute in to the function, it will satisfy.

Answer 41

ok so

x= 2/3 x= -3

Answer 42

yes, that is the final answer, 100% correct

Answer 43

okay( thank you SOOO much!