Question

derivate:
y=cube square of t(t^2+t+t^-1)

Answer 1

\[\sqrt[3]{t}\left( t^{2} +t+t ^{-1}\right)\]

Answer 2

This is done by product rule.
$$y' = t^{1/3}(2t + 1 - t^{-2}) + \frac{1}{3}t^{-2/3}(t^2 + t + t^{-1})$$

Answer 3

cool