Rationalize the denominator
square root 3 over sq.root26+5 does anyone know how to figure this out?

Question

anonymous · Answer

Check out: http://www.helpalgebra.com/articles/rationalizedenominator.htm

amistre64 · Answer

you have to multiply the top and bottom by sqrt(26+5)  if that is in your denominator.

What happens is the squareroots cancel and your left with 26+5 on the bottom.

Actually, yo need to write the problem better cause it is kinda hard to tell what it is :)

anonymous · Answer

If this is your equation:$$\sqrt{3}/\left( \sqrt{26} + 5 \right)$$, then you need to multiply (numerator & denominator) by what's called the conjugate radical of the denominator:
$$\sqrt{26}-5$$

amistre64 · Answer

mrslange knows it :)