Question

how do you solve 2x^4/3-2=160?

Answer 1

2.99

Answer 2

Oops that's not right sorry

Answer 3

hahhah yeah...

Answer 4

its like solving square roots and radical equations

Answer 5

27

Answer 6

^^ That's the answer sorry about that haha

Answer 7

okay but like how do u do it....hahah

Answer 8

explllain :)

Answer 9

2x^(4/3) = 162
x^(4/3) = 81
x = 81^(3/4)
x = 27

Answer 10

This is because

(x^(4/3))^(3/4) = (81)^(3/4)

Answer 11

\[2x ^{4/3} - 2 = 160\]
\[x ^{4/3} = 81\]
\[\sqrt[3]{x^{4}} = 81\]
\[x ^{4} = 81^{3}\]
x = 27

Answer 12

Make me a lifesaver :)

Answer 13

I beat krb686

Answer 14

thankss guys!!!

Answer 15

thankss guys!!!

Answer 16

i have more questions hold on....hahah

Answer 17

i have more questions hold on....hahah

Answer 18

okay so the next section is inverse relations and functions...

Answer 19

wait forgett that haha..okay so how do u graph square roots and radical functions like wtff i dont get itt.... one problem is like y=-\[y=-\sqrt{x+2}\]

Answer 20

Do you know how to find the domain of a function?

Answer 21

yeaahh

Answer 22

So the domain of the function here is [-2,infinity)

Answer 23

If we were looking at y=(x+2)^(1/2) the function would be increasing since the bigger the x the bigger the y.

Answer 24

But we have y=-(x+2)^(1/2), so the function is getting smaller for big x

Answer 25

If you can graph the function y = root(x), then take that graph and shift it to the left by 2, and flip it upside down

Answer 26

ohh so thats all?

Answer 27

thats easyy

Answer 28

Yep! When there is an additive factor inside of the function with the x, a positive # shifts to the left and negative shifts to the right.

And a negative multipler on the outside flips it upside down.

Answer 29

No technically the domain includes values less than negative 2, which would be considered i values (or in this case imaginary), this is very useful in electrical engineering where there is an imaginary and real domain. Very useful in euler's method as well. The values don't exist if they are indeterminant or non-existent in general, and krb is correct in the fact that it will be shifted and the values will flip.

Answer 30

what about if its like... \[y=\sqrt{x+2}+1\]?

Answer 31

No the domain includes values greater than -2

Answer 32

Okay so the inside 2 shifts it to the left 2, and the outside 1 shifts it UP 1

Answer 33

Shift left 2, and increased y intercept by 1

Answer 34

mathgenius101 is technically correct, if the domain is allowed to include all numbers not just reals.

Answer 35

He didn't specify if the domain included complex values. So technically there could be a domain x<-2, imaginary is still technically a complex number.

Answer 36

im pretty sure we are only talking about real numbers here

Answer 37

True

Answer 38

hes in college algebra

Answer 39

You should never be an electrical engineer.

Answer 40

or some type of algebra

Answer 41

wait okay so..

Answer 42

see you confused him

Answer 43

what about if theres a number (either neg or pos) before the square root?

Answer 44

umm im not a him if youre talking about me...hahahha

Answer 45

Multiplied or added/subtracted?
Multiplied flips it either up or down, added or subtracted shifts it up or down.

Answer 46

Yeah, stop assuming like how you're assuming it's a real number. She's a girl.

Answer 47

hahha love ya math genius <3 <3

Answer 48

r u guys like math nerds....

Answer 49

I guess you could say that. Soon-to-be engineers.

Answer 50

i gotta go study more then sleep. BYEEE NEW FRIENDSSSSS THANKS FOR THE HELP :) <3

Answer 51

i gotta go study more then sleep. BYEEE NEW FRIENDSSSSS THANKS FOR THE HELP :) <3

Answer 52

dont miss me too muchhhhhh!!! hahahhaha

Answer 53

I'll try not to ;)

Answer 54

i like math genius the best...youre the only one who responds to my pointless comments

Answer 55

i like math genius the best...youre the only one who responds to my pointless comments

Answer 56

k bye...for reall..