Question

(secx + tanx)^2 = (1+sinx) / (1-sinx)

Answer 1

wow, what a question, sstarica, you think you can handle it?

Answer 2

=D

Answer 3

thinking :P

Answer 4

i think you should use google first =D

Answer 5

sstarica, if you become my fan, I will become yours, a win win

Answer 6

\[= 1+sinx / 1-sinx\]\[= \sec^x + 2secxtanx + \tan^2x\]\[= 1 + \tan^2x + 2(sinx/\cos^2x) + 2(\sin^2x/\cos^2x)\]\[= 1 + ((2\sin^2x + 2sinx)/\cos^2x)\]\[= 1 + (2sinx(1+sinx)/1-\sin^2x)\]\[=1 + (2sinx(1+sinx)/(1-sinx)(1+sinx))\]\[=1 + (2sinx/1-sinx)\]\[= 1(1-sinx) + 2sinx/1-sinx\]\[= 1-sinx + 2sinx/1-sinx\]



^_^

Answer 7

:O

Answer 8

= 1 + sinx / 1-sinx

:)

Answer 9

no need for google :)

Answer 10

wow, you are smart

Answer 11

2nd line should be sec^2 x and not sec^x ^^" typo sorry

Answer 12

but I LOVE google =D

Answer 13

we all are ^_^

Answer 14

wait a min....ANGOO! :D

Answer 15

that's you!

Answer 16

Dr. GOO LOL!

Answer 17

=D

Answer 18

another account? lol, I'm slow sorry ^^" just figure u out =P

Answer 19

figured*

Answer 20

why another account? bored? :D

Answer 21

yes =D

Answer 22

got a better name LOL

Answer 23

I'll call you GOOBOO :D!!!!

Answer 24

fanned you

Answer 25

fine fine lol

Answer 26

happy? =P

Answer 27

yes, VERY =D

Answer 28

seriously, lol

Answer 29

ok, I got to go for now, book plane tickets for my dad

Answer 30

see you later smart lady

Answer 31

alright , see you then ^_^

Answer 32

alright Dr.G