Question

How would you find the acceleration, velocity, and speed of particle with position function r(t)=2i+6tj+12t^2k at the point (2,0,0)?

Answer 1

Velocity= <0,6,0> speed is the magnitude of V which is 6 and acceleration is 0 at (2,0,0)

Answer 2

you just need to take the derivative once to get the velocity, and derive the position function twice to get the acceleration, and then just substitute for the point (2,0,0)

Answer 3

v=6j+24tk v(2,0,0)=0
a=24k a(2,0,0)=0