Question

Find the polynomial equation with real coefficients that has the given zeros..
1-5i and 1+5i

Answer 1

not sure if it's right... but I'll do it this way...
[x-(1-5i)][x-(1+5i)]
then just expand it out and collect like terms and use i^2=-1
= x^2-2x+24

Answer 2

x^2 - 2x + 26 *

Answer 3

ah.. yes yes 26.. sorry XD

Answer 4

can you tell me how you got that ?

Answer 5

(x-1+5i)(x-1-5i)
=x²-x-5ix-x+1+5i+5ix-5i-25i²
=x²-2x+1-25i²
=x²-2x+1+25
=x²-2x+26
I don't know if there's a faster way...

Answer 6

THANK YOU SOOOOO MUCH! I get it!!!

Answer 7

Yay! Happy to help ^o^