Question

Find the area between y=4x and y=x^2?

Answer 1

here the graph y= 4x cuts the graph y=x^2 at 2 points.
we can find the points by equating the 2 graph.
4x = x^2
x=0 & x= 4
let the area under the 1st graph is a & area under the 2nd graph is b.
then the required area is a-b.
u can find the areas by integration .

Answer 2

hey u have to find the area from x=0 to x=4 only in both case. then u can do the other manipulation .

Answer 3

so what do you get for the area?

Answer 4

by integration.
\[a=\int\limits_{0}^{4}4x dx =2x ^{2}
=2*4*4-0 =32\]
\[b=\int\limits_{0}^{4} x ^{2}dx = x^{3}/3 = 4^{3}/3-0 =64/3\]

area = a-b = (32-64/3) = 32/3