A triangle drrawn with angles of 40 degrees at the top and 65 degrees on the far right with a measurement of 72 on one side(right side line) sits next too a triangle of a 40 degree angle at the top with a line measurement of 52 on the left side and 45 line measurement on the right side. What would the length of all the missing sides and missing angles be?

Question

A triangle drrawn with angles of 40 degrees at the top and 65 degrees on the far right with a measurement of 72 on one side(right side line)  sits next too a triangle of a 40 degree angle at the top with a line measurement of 52 on the left side and 45 line measurement on the right side.  What would the length of all the missing sides and missing angles be?

anonymous · Answer

In the first triangle the last angle is given by 180-40-65=...

amistre64 · Answer

you can use a mixture of the law of cosine and the law of sines to determine these...

amistre64 · Answer

2nd triangle:

a=52; C=40 b=45

Find B (bottom left angle), A (bottom right angle), and c (bottom line)

c^2 = a^2 + b^2 -2ab cosC

c^2 = 52^2 + 45^2 -2(52)(45)(cos(40))

c^2 =

amistre64 · Answer

c^2 = 4729 - 4680(cos(40))

amistre64 · Answer

c^2 = 1143.9120062031827952528023954006

c = 33.8218  if i did it right....

amistre64 · Answer

sinA       sinB          sinC
---- =  ----  =    ----
  a            b             c

anonymous · Answer

Thank you very much