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The product of two consecutive positive integers is 19 more than their sum. Find the integers.
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Two consecutive integers are "x" and "x+1" Their sum is x + x + 1 = 2x + 1 So x(x+1) = 2x + 1 + 19 add like terms x(x+1) = 2x + 20 distribute x^2 + x = 2x + 20 set it = to 0 x^2 - x - 20 = 0 ... Now how do you solve these. Do you want me to factor or use the quadratic formula?
wouldnt it be (x-5)(x+4)?
Yes which then the answer are either 5 or -4 so the two integers are 5 and 6 5(6) = 5 + 6 + 19 and -4 and -3 -4(-3) = -4 + -3 + 19
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