Question

2sin^2x-sinx-1=0, solve for x

Answer 1

factor this thinking about the entire sinx as the variable, then set each factor to zero and solve from there

Answer 2

Can you factor 2x^2 - x - 1 = 0

Answer 3

yeah, put 2x in one parentheses and x in the other and try factors of 1...not much choice of course

Answer 4

Just making sure you understood what jpick said

Answer 5

(sinx-1)(2sinx+1)=0
sinx=1 and 2sinx=-1
sinx = 1 and sinx = -1/2
x = sinx^-1(1) and x = sinx^-1(-1/2)
x= \[x=\pi/2 and x=-\pi/6\]

Answer 6

x=π/2 and
x=−π/6