Question

Using Calculus techniques, find the approximate value of:

Answer 1

\[\sqrt[3]{25}\]

Answer 2

find an approximate cuberoot; and keep reiterating? I know there is a certain "way" you can get to it.... but I forget it right off hand.

Answer 3

f(x) = f'(x) + ....

Answer 4

x^(1/3) gets us f'(x) = (1/3)x(-2/3)

1
--------- = the slope of your "line equation"
cbrt(x^2)

Answer 5

y = 1/cbrt(x^2) + b i think is the way it can go...then find out what this value is for x and reiterate it again tilll you get to a level of accuracy that you are comfortable with