Question

f(x)=x^4-6x^3+10x^2+2x-15

Answer 1

What do you need to find?

Answer 2

u need to solve for x

Answer 3

1,3,5,15
-1,-3,-5,-15

lets try x=3

3 | 1 -6 10 2 -15
0 3 -9 3 15
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1 -3 1 5 0 <-remainder is zero, this is a solution

(x-3)
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lets try x = -1


-1 | 1 -3 1 5
0 -1 4 -5
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1 -4 5 0 <- remainder is zero, this is a solution.

(x+1)(x-3) is what we got so far..
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the rest is a quadratic that can be figured out the normal way:

Answer 4

x^2 -4x +5 = 0

16 - 4(5) = 16 - 20 = -4... there are no more real solutions the answer is:

(x-3) (x+1) (x^2 -4x +5) since the quadratic is zeroless that leaves:

x = 3 or x = -1 as our solutions.

Answer 5

wow thanx that did help