Question

what is the derivative of:
2 square x (not sure how to do)

and

(1-2x)/x^3 I get 3x^3(-1+2x) not sure if correct

Answer 1

sorry for the last one my answer is 3x^2(-1+2x)

Answer 2

u can rewrite square of x by x^1/2

Answer 3

2(sq.x)=2(x^1/2)

Answer 4

multiply the exponent by the degree and subtract 1 from the exponent

Answer 5

\[2\sqrt{?}\] sorry I can't get it in corrrectly the ? should be the x

Answer 6

take the 2 out and derive sqrt(x); or x^(1/2)

1/2sqrt(x)

now put the 2 back in:

2/2sqrt(x) = 1/sqrt(x)

Answer 7

(1-2x)/x^3 use quotient rule :)

x^3(-2) - (1-2x)(3x^2)
--------------------
x^6

Answer 8

\[\frac{d}{dx}[ \frac{(1-2x)}{x^3}] \]
\[= \frac{d}{dx}[ (1-2x)x^{-3}]\]
\[= (1-2x)\frac{d}{dx}[ x^{-3}] + x^{-3}\frac{d}{dx}[ (1-2x)]\]
\[ = (1-2x)(-3x^{-4}) + x^{-3}(-2)\]
\[ = -3x^{-4} + 6x^{-3} - 2x^{-3}\]
\[ = \frac{4x-3}{x^4} \]

Answer 9

-2x^3 -3x^2+6x^3

4x^3 - 3x^2

(4x-3)x^2
--------
x^4 x^2

4x-3
----- maybe??
x^4

Answer 10

thanks, i have to go for now , i will check back in about and hour

Answer 11

polpak did it good :) or we messed up toghter lol

Answer 12

I prefer to ignore the quotient rule and use product rule with a negative exponent.

Answer 13

potato<>potato :)

Answer 14

I thought potato = potato ;p

Answer 15

There is another way to look at mom.

(1-2x)/x^3 can be rewritten to appear as (1-2x)(x^-3)
\[(1-2x) *x ^{-3}=x ^{-3}-2x ^{-2}\]

Answer 16

This may be in a more familiar form you can now simply take the derivative to be:

\[-3x ^{-4}+4x ^{-3}\]

simplifying will obtain the results of polpak and amistre64