Question

at what point on the curve x^2-y^2+x=2 is the tangent line vertical?

Answer 1

can we take the derivative?

Answer 2

2x -2yy' +1 =0

-2x -1
------ = y'
y

when y=0

Answer 3

forgot a couple details, but the result is the same

Answer 4

x^2 + x = 2

x^2 +x -2 =0

x = -4 and x= 2

the point (-4,0) (2,0)

Answer 5

doh....divide by 2

Answer 6

(-2,0) and (1,0)

Answer 7

k, that is what i was going to tell you, thanks a lot

Answer 8

by all means, when im wrong let me know :)