Question

dos the system have on solution, no solution, or an infinite number of solutions?
x+y=6
x+y=4
a. one. b. none. c. infinite number

Answer 1

none, x+y can only have one solution..otherwise:

4+5 = 9

4+5 = 3

just nonsense i tell ya....nonsense!! :)

Answer 2

lol thank yiu

Answer 3

graphically, and if it aint a word it should be, these are parallel lines that never intersect

Answer 4

How about this one? x + y =4
x + y =0

Would x=2\[y=\sqrt{4}\] be an answer????

Answer 5

same slopes, different "y intercepts"....nope

Answer 6

y=-x

y = -x+4

-x = -x+4

-x+x = 4

0 = 4

nonsense :)

Answer 7

Just wondering, as the square root of 4 is +2 or -2 and they when substituted for y and if x=2 would produce those two answers. Kind caught me off guard.

Answer 8

2+2 = 4
2+2 = 0 still not a good solution :)

Answer 9

Square root of 4 is +2 (by definition), kids [NOT -2]

Answer 10

even if -2 was available to us it doesnt change the results of 0=4; which is absurd....

Answer 11

He was implying it could equal 2 or -2 (one in each) - yes, of course that is absurd, but I thought I would tell him the flaw in his thinking.

Answer 12

yeah, 2 = -2 is equally nonsensical :) If we cant pin down x at a single value, then its futile.

Answer 13

Thanks, you can see where the flaw would 2 +(+2)=4
and 2 + (-2) = 0 However, it has been revealed that the negative root of a variable is not usable or shouldn't be used in this case. Now please note. There was no way to solve the two equations to come up with that ridiculous answer!