Question

how much pure acid must be added to 8mL of 20% acid solution in order to obtain a 50% acid solution?

Answer 1

So set it up the same way I did the last one. If you run into trouble, ask.

Answer 2

8(.2) + y(1) = (8+y)(.5)

solve for "y" :)

Answer 3

thats what i came up with! thanks

Answer 4

ok i tried to solve this and got 1.2 and thats not one of the mulitple choice options what am i doing wrong

Answer 5

20(8) + 100(x) = 50(8+x)
100x + 160 = 400 + 50x
50x = 400 - 160
5x = 24
x = 4.8 ml