Question

ok im lost on trying this hw problem please explain how to do this

(x-1)^2/5 = 4 im not sure how to factor the 2/5 power

Answer 1

use logs:

log(x-1^2/5) = log(4)

2/5 log(x-1) = log(4)

log(x-1) = 5/2 log(4)
log(x-1) = log(4^5/2)

x-1 = 4^(5/2)

x = 1 + 4^(5/2)

Answer 2

or:

5root((x-1)^2) = 4 ^5 each side

(x-1)^2 = 4^5 now square both sides

x-1 = sqrt(4^5)

x = 1+sqrt(4^5)

Answer 3

x = 1 + sqrt(4*4*4*4*4)

x = 1+5sqrt(4)

x = 1+5(2)

x = 11 by chance?

Answer 4

i missed something in that...im sure of it :)

Answer 5

this is suppose to be done by hand, i could easily throw it in the calculator and graph the equation for an answer. we have not learned anything about log yet
awwwh that would work for me :) thx
x is 32

Answer 6

x = 33 ...maybe

Answer 7

eeerr 33 i mean

Answer 8

my 5sqrt(4) up there is a result of my own stupidity....just ignore the person behind the curtain :)

Answer 9

lol thx yea i got it now i totally forgot how to do this

Answer 10

what is the 5root(32^2) anyway...

Answer 11

youre welcome :)

Answer 12

4