Question

in simplest form: 2x^2 + 5x - 7/x + 4 times x^2 + 4x/x^2 - 2x + 1

Answer 1

Hi Angelia

Answer 2

\[(2x ^{2}+5x-7)/(x+4)\times(x ^{2}+4x)/(x ^{2}-2x+1)\] Is this your equation?

Answer 3

2x^2 + 5x - 7 x^2 + 4x
------------- x -----------
x + 4 x^2 - 2x + 1

You have to factor each binomial/trinomial
(2x + 7)(x - 1) x(x + 4)
------------- x ---------
(x + 4) (x - 1)(x - 1)

You then cancel the (x + 4)'s and the (x - 1)'s (only 1 of these on the bottom)

x(2x + 7)
----------
x - 1

Answer 4

I guess it was lol

Answer 5

Thanks blexting you really helped, I have one more problem

Answer 6

Sure.. go ahead

Answer 7

12x + 48/6x-15 times 4x^2-25/x^2 + 9x + 20

Answer 8

12x + 48 4x^2 - 25
------------- x ---------------
6x - 15 x^2 + 9x + 20

12(x + 4) (2x + 5)(2x - 5)
---------- x ---------------
3(2x - 5) (x + 4)(x + 5)

Cancel the (x + 4) and the (2x - 5) cancel the 3 up into the 12 leaving 4

4(2x + 5)
---------
x + 5

Answer 9

When I was trying to do this problem on my own I messed up on the part 4x^2-25 I didn't have it factored correctly. You've been a big help to me. Thanks a lot!!!!!

Answer 10

Any time... Just remember that is the difference of two squares

(2x)^2 and (5)^2 so you take what is in the ( )'s and add them and subtract them.

(2x + 5)(2x - 5)

Answer 11

I don't have any homework tonight but I may have to have help tomorrow night if that's okay. Will you be on this site or the one you referred me to?

Answer 12

Email me and I will come on this site.

Answer 13

okay, I'll email you then. Hope you have a good night. Bye!!!

Answer 14

You too...