Question

completing the square for -3x^2-6x+9 and graph a x-int and y-int and vertex point

Answer 1

-3(x^2 + 2x ) + 9 = 0
-3(x^2 + 2x + 1) + 9 = -3
-3(x + 1)^2 +12 = 0

Vertex (-1,12)

Answer 2

how do i find two points to graph?

Answer 3

Pick any point... let's say x = 2
so y = -3x^2 - 6x + 9

so y = -3(2)^2 - 6(2) + 9
y = -12 - 12 + 9
y = -15

so (2,-15)

Let's say x = 0
y = -3(0)^2 - 6(0) + 9
y = 0 - 0 + 9
y = 9

so (0,9)

Answer 4

thank you!!