Question

how do i get my quadratic answer in decimal form

Answer 1

divide......

Answer 2

or do you mean that sqrt part?

Answer 3

\[33\pm \sqrt{65}\over 32\]

Answer 4

split it up int0 its parts:

33/32 + sqrt(65)/32

33/32 - sqrt(65)/32

.969
-----------
33 | 32.00000
- 297
----
230
- 198
----
320
- 297
-----
230 <- this is repeating so we use this symbol

--
.96 that is .96 with a bar above it to indicate that it is a repeating decimal

Answer 5

the trick to doing the sqrt part is really to know that x^2 + 2xy + y^2 is the key to your results. We we seperate the number up into groups of 2 starting at the decimal and going in both directions, for example:

12345.654 becomes 1 23 45. 65 40 00 00 00

Answer 6

your sqert(65) is already in a group of "2" so we have:

------------------
\/65. 00 00 00 00 00

Answer 7

now we need to find a number for "x^2" that is close to but less than the first grouping; in this case close to but less than 65. 8^2 = 64; so lets use that:


8.
------------------
\/65. 00 00 00 00 00
-64
--------
1 00

we have our "x^2, now we need to "2x" and find "y" to add to this.

8.
------------------
\/65. 00 00 00 00 00
-64
--------
2x+y| 1 00
16 __ |

0 is the only thing we can use for y because 160 is greater than 100 and we cant use anything else.

Answer 8

8. 0 y
------------------
\/65. 00 00 00 00 00
-64
--------
160 | 1 00
-------
160+ y | 1 00 00

and continue

Answer 9

sweet, thanks!

Answer 10

its either that or use a calculator :)