Question

log_4(x)+log_8(x)=1

Answer 1

b log x + b log y = b log (x.y)
it have the same base..the base of this problem is 10...
then
according to the equation above:
log ( 4x.8x) = 1
log (4x.8x) = log 10
log (32 x^2) = log 10
32x^2 = 10
x^2 = 10/32
x = \[\sqrt{10/32}\]