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FInd the vertex, focus, and directix of the parabola. x=2y^2
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a parabola has the expression: y^2 = 4ax ....or some similar topology to it..
if we rearrange your expression we get: (1/2)x = y^2 which gets us looking close to normal again
4a = 1/2 a = 1/8 ; the distance from the vertex to the directix os 1/8 ; and the distance from the vertex to the focus is 1/8
the parabola opens to the left, and it is centered onthe xaxis; so.... vertex = (0,0) focus = (0,1/8) and directix is the line x= -1/8
thanks =)
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youre welcome.... its always good to review the basics ;)
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