Question

Simplify the trigonometric expression.

cos[x]/ tan[x] + sex[x]

Answer 1

Where is the sec(x) in the denominator or by itself

Answer 2

by itself

Answer 3

cosx
--- + sec x
tanx

cosx 1
---- + ----
sinx sinx
----
cos x

cosx divided by sinx/cosx is actually cosx times cosx/sinx

cos^2x 1
------ + ------
sinx sinx

cos^2x + 1
----------
sinx

That may be as far as you can take it...

Answer 4

bleh, that's wrong said loco :( but good that you've tried too blex ^_^

Answer 5

thanks blex :)

Answer 6

The last step blex did is wrong. cos^2 is not equal to cos^2+1.

Cos/Tan + Sec
Cos^2/Sin + Sec... Expanding the tangent into its components.
(Sin^2 - 1)/Sin + Sec... Using the identity sin^2 + cos^2 = 1.
Sin^2/Sin - 1/Sin + Sec... Separating out the numerator of the fraction.
Sin - Sec + Sec... The first term has a sin that cancels, the second term is just secant.
Sin... Both the secants cancel and you're left with just sin.