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Mathematics 28 Online
OpenStudy (anonymous):

find two consecutive intergers who cubes differ by 127

OpenStudy (anonymous):

Call them x, y, x>y \[x^3 - y^3 = (x-y)(x^2 + xy + y^2) \] However, x = y+1 , so we actually have: \[((y+1)-y)((y+1)^2+y^2+y(y+1)) = 3y^2+3y+1 = 127 \]

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