Question

What is the domain of 1/sqrt3x+1?

Answer 1

\[1/{\sqrt{3x+1}}\]

Answer 2

is that what is says?

Answer 3

Yes.

Answer 4

ok when is the bottom zero

Answer 5

since the denominator is not allowed to be 0
and
the input of the square root is not allowed to be negative,

you solve for sqrt(3x+1) = 0
and
3x+1 < 0

The solution of these are the x's you are not
allowed to use.

so the domain would be all real numbers except the above.