Question

points of discontinuity?
y = cot x, [0, 2 \[\pi \] ]

Answer 1

\[\cot(x) = {1 \over \tan(x)}\]

so there's a discontinuity, whenever tan(x) == 0... 'cause a division by 0 is not defined.

Answer 2

cotx = (cosx)/(sinx)
Where is this function not defined? i.e. where is sin(x)=0? Because at this point, cotx will be undefined because you cannot divide by zero. So find all points from 0 to 2 pi where sinx is 0.