Question

find two consecutive negative odd integers such that the square of the lesser integer is 40 more than the square of the greater integer

Answer 1

9 ,11.

sounds weird :P

Answer 2

nop

Answer 3

i mean-9,-11

Answer 4

how did you get that?

Answer 5

it amounts to 81 and 121

Answer 6

i think se said consecutive

Answer 7

wait im sorry buit i dont understand like how you would do that prblem now..ciykd someone explain that? thanks

Answer 8

ok for for a general formula try -x^2 =(-x+2)^2 + 40

Answer 9

but then dont the x's cancel out?

Answer 10

ok

Answer 11

u start with
-x^2=(-x+2)^2+40
multiply the square ull get
-x^2=x^2-4x+4

Answer 12

sorry
-x^2=x^2-4x+4+40

Answer 13

oh ok thank you guys!!

Answer 14

wait where does the 4x come from?