Question

describe the relationship between the graphs of the linear equation y=1/3x+10 and 3y=9x+2

Answer 1

did you type the question wrong?
it looks like it's going for a perpendicular relationship, but that would be a negative reciprocal
if not, the second line is 9 times as steep (slope wise) as the first...
and they would intercept at

1/3x + 10 = 3x + 2/3
x + 30 = 9x + 2
-8x = -28
x = 7/2
y = 335 / 30 = 67 / 6

intersect at (7/2, 67/6)

Answer 2

the equations are: y=-1/3x +10 and 3y=9x-2

Answer 3

i forgot a (-)

Answer 4

it sounds like you know what you are doing though! lol

Answer 5

lols then i was right in the first sentence.
ignore the rest
it's perpendicular

Answer 6

i am just not sure how to solve the equation...how do i start?

Answer 7

the definition of perpendicular lines requires that the slopes of the lines have to be negative reciprocals. Negative reciprocals means that it's negative and inversed (1/x)

so in your example
y=1/3x+10 and 3y=9x+2

change both to y = mb + c
y=-1/3x+10
y=3x+2/3

so the slopes are -1/3 and 3
if you take the negative reciprocal of -1/3 would be
\[\frac{1}{-\frac{1}{3}}* -1\]
which would equal 3

Since they are negative reciprocals, they are perpendicular
it's a rule
memorize it
just like how parallel lines have the same slope, it's the same idea
perpendicular lines are negative reciprocals


cheers ^_^

Answer 8

thank you so much

Answer 9

no prob, good lucks