Question

There is a particle that moves on a line with the velocity v = 12sqrt(s) where s is the distance from the origin.
If s = 1 when t = 0, what is the value of s when t = 1 ?

Answer 1

i'm pretty sure you typed the question wrong, velocity should be a function of time so it should be v = 12 sqrt (t)
integrate the function, we'll call the new function s
you get
s(t) = 8t^(3/2) + C
plug in t = 0, which would make for the function
s(0) = 8t^(3/2) + C
1 = C
so s(t) = 8t^(3/2) + 1
s(1) = 8*1(3/2) + 1
s(1) = 9

Answer 2

I thought the same thing at first, but I copied it exactly the way it is.

The answer has to be 49

Answer 3

hmm....is there anything else to the question?
i'm sorry for asking this, but it's hard to see velocity as a function of distance.. you usually see it as a function of time
and i don't know how you're supposed to integrate that then, what would be the new function?

Answer 4

nope, that's all its written.
I am thinking that parametric equations is the key.
But the question is too specific for me to look it up.

Answer 5

I'm sorry, i can't help you
even if we integrate with respect to s it wouldnt matter
because s is 0
so constant would be very small.
plugging 0 OR 1 would give you a small number
49 is a huge number...
sorry, but good luck

Answer 6

It's all right.
Thanks for trying.