Question

solve for x: x^2 + 5x is > or = 6

Answer 1

x^2+5x-6>=0
(x+6)(x-1)>=0
when is this LHS zero?

Answer 2

when x=___ and x=___?

Answer 3

What is LHS..?

Answer 4

You would use the (x + 6)(x - 1) >= 0

When x <=-6 or x >= 1

Answer 5

from the (X+6) you would then solve for x for both giving you the positive 1 and negative 6 correct?

Answer 6

That would give you when it = 0, but when would it be > 0... see my earlier response

Answer 7

Then where are you getting the positive and negative...... your doing x+6=0 or x-1+0 ... right

Answer 8

(-inf,-6]u[1,inf)

Answer 9

What.... does that say