Question

I need to verify I have the correct vertex of the following..

f(x)=x^2-x+1

I also am unable to figure out how to get the values from the graphing calculator. Anyone know please?

Answer 1

to find the vertex you'll have to take x = -b/2a then find f(-b/2a) :)

Answer 2

so , I have the following:

a = 1, b = -1 and x = 1

\[x = \frac{1}{2}\]

and

\[f(\frac{1}{2}) = (\frac{1}{2})^2 -\frac{1}{2} + 1 = \frac{3}{4}\]

so your vertex is :

\[(\frac{1}{2}, \frac{3}{4})\]
correct me if I'm wrong ^_^

Answer 3

Wow, that is what I JUST got when I zoomed in my calculator.

Answer 4

That is wonderful. But on that calculator, how do I find the value?

Answer 5

hmm, I'm not sure, I've never used a graphing calculator before :) I just simply sketch ^_^

Answer 6

why don't you sketch it?

Answer 7

Oh my goodness, thank you . I have been trying to find the vertex formula.

Answer 8

I did sketch it..

Answer 9

most welcome :)

Answer 10

then you can easily plot the vertec from your sketch :)

Answer 11

vertex*

Answer 12

Its asks for values such as XMIN, XMAX, XSCL, YMIN, YMAX AND YSCL

Answer 13

the question? or the graphing calculator?

Answer 14

IIs on the calculator, but it never changes from -10 or 10..

Answer 15

those values should show on the calculator..but i have no clue how to find them and it's part of my answer the teacher wants

Answer 16

lol, I wish I can get my sister here, she uses a graphing calculator , she'll prolly know the answer, but school lol

Answer 17

I'm sorry :(

Answer 18

LOL. Thank you for your help. I will figure it out tomorrow..thanks a bunch