Question

use elimination method to solve system of equations; 5u+3v=-15 2u+v=-6

Answer 1

5u + 3v = -15 (1)
2u + 1v = - 6 (2)
6u + 3v = -18 (2)*3
1u + 0v = -3 (2)*3 - (1)

Then back substitute into (1)

5*-3 + 3v = -15
-15 + 3v = -15
3v = 0
v = 0

Confirm using (2)
2*-3 + 1v = -6
-6 + 1v = -6
1v = 0
v = 1

u = -1, v = 0

Answer 2

Sorry u = -3, v = 0