Question

I have to graph this parabola.
(5y^2)+10y-x+4=0

Can somebody show me the steps on how to do this

Answer 1

are you sure its entered coorectly?

Answer 2

yes.

Answer 3

then its most likely e geometric equation of a parabola

Answer 4

set it equal to x
x = 5y^2 +10y +4
this will give us a sideways parabola

Answer 5

complte the square for the ys

Answer 6

right
do you know how to find x and y intercepts?

Answer 7

is it this ( -b/2a , 4ac-b^2/4a) ?

Answer 8

y^2 +2y = x/5 -4/5

Answer 9

find vertex using
y = -b/2a
where a,b,c are the coefficients

Answer 10

(y+1)^2 = x/5 - 4/5 +1

Answer 11

... x/5 + 1/5 =1/5(x+1)

Answer 12

(y+1)^2 = (1/5)(x+1) has the form y^2 = 4ax

1/5 = 4a

a = 1/20

Answer 13

the center is at (-1,-1) ang opens to the right

Answer 14

by center I mean vertex ;)