Question

graph the following. Identify wheather or not the graph is a funtion. Then evalutute the graph at my specified domain.
F(x)= x+5 x<-2
X^2+2x+3 x=>-2
F(x) (3)=
F(x) (-4)=
F(x) (-2)=
Please help me...i will give you a medal if you can help

Answer 1

Yes, it's a piece-wise function, but still a function.

For f(3) you would evaluate it at 3, with whichever equation is at 3. In this case, it's x^2+2x+3. So you plug in 3. 3^2+2(3)+3 = 18

f(-4) you would use x+5 so it would be -4+5=1

f(-2) would be x^2+2x+3 = 3

Hope that helps!

Answer 2

use the link provided previously. It worked well for the first one.

Answer 3

@kaiyne what are the points? to graph it

Answer 4

Well, value given is the x value and you solve for the y value. So it ends up being (3,18), (-4,1) and (-2,3)

Does it make sense how I got those?

Answer 5

alittle i have one more can i ask you that one?

Answer 6

Sure, what is it?

Answer 7

F(x) 2x+1 x =>1
x^2+3 x<1
F(-2)=
F(6)=
F(1)=

Answer 8

f(-2) is less than one, so its x^2+3, or (-2)^2+3 = 7. (-2,7)

f(6) is greater than one, so you use 2x+1 or 2(6)+1 = 13. (6,13)

f(1) is equal to 1, so its still on 2x+1 (since that is x=>1). It ends up being 2(1)+1 = 3. (1,3)

Answer 9

is it a function?

Answer 10

thanks so much i get it now :)