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You have 1.50mL of a urine specimen. The assay you must do requires a 1/25 dilution. How much water must be added to the specimen to achieve this dilution?
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urine? eww!!!
1/25 = .04 as a decimaled percent. 1.5(1) + y(0) = (1.5+y)(.04)
1.5 = .06 + .04y 1.5 - .06 = .04y y = 1.44/.04 = 144/4 = 36 36mL of water...and some soap?
hahaha. thank you :)
i did get 36 as well!
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yay!! we shuld join mensa :)
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