Question

You have 1.50mL of a urine specimen. The assay you must do requires a 1/25 dilution. How much water must be added to the specimen to achieve this dilution?

Answer 1

urine? eww!!!

Answer 2

1/25 = .04 as a decimaled percent.

1.5(1) + y(0) = (1.5+y)(.04)

Answer 3

1.5 = .06 + .04y

1.5 - .06 = .04y

y = 1.44/.04 = 144/4 = 36

36mL of water...and some soap?

Answer 4

hahaha. thank you :)

Answer 5

i did get 36 as well!

Answer 6

yay!! we shuld join mensa :)