Mathematics
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OpenStudy (anonymous):
evaluate 15 C 4 and 15 p 4
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OpenStudy (anonymous):
do u understand it
OpenStudy (anonymous):
No.
OpenStudy (anonymous):
What's C and p?
OpenStudy (anonymous):
Its part of the formula
OpenStudy (anonymous):
they are combinations and permuatations
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OpenStudy (anonymous):
nCr = n! / (n-r)!r!
OpenStudy (anonymous):
nPr = n! / (n-r)!
OpenStudy (anonymous):
I see. Never seen it before!!
OpenStudy (anonymous):
there are buttons on calculators for it
OpenStudy (anonymous):
15C4 = 1365
15P4 = 32760
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OpenStudy (anonymous):
conclusion , there are alot more arrangements if you consider order !
OpenStudy (anonymous):
so then u devide them
OpenStudy (anonymous):
its combinatorics , a bit of a painful topic, a bit tricky sometimes
OpenStudy (anonymous):
what u do with those 2 now?
OpenStudy (anonymous):
what do you mean "what do you do with them now" , you asked the question :|
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OpenStudy (anonymous):
yeah but thats not the answer
OpenStudy (anonymous):
its only suppose to be one answer because ur evaluation
OpenStudy (anonymous):
:|
OpenStudy (anonymous):
so you meant 15C4 + 15P4 :|
OpenStudy (anonymous):
i said and
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OpenStudy (anonymous):
yeh :|
OpenStudy (anonymous):
would it be 24
OpenStudy (anonymous):
you could possibly be referring to the multiplication of them , but thats really badly worded
OpenStudy (anonymous):
and is add " of" is mutiplication
OpenStudy (anonymous):
that was right can u help me with the one I just posted up sorry
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OpenStudy (anonymous):
Its the same stuff just diff question