Question

(2b-3)(3b-8)=0
am i correct with the answer of -6 and 8 for being the solution to this?

Answer 1

Try substituting in the solutions:
(2(-6) -3)(3(-6) - 8) = 0
(-12-3)(-18-8)=0
(-15)(-26)=0

So they are not the solutions.

Answer 2

Instead set each factor equal to 0 and solve:
2b-3 = 0
and
3b-8 = 0

Answer 3

i dotn get what the solutions would be somehow i keep coming up with -6 and 8

Answer 4

2b - 3 = 0
add 3 to both sides
2b = 3
now divide by 2
b = 3/2

Answer 5

I think you were multiplying on the last step instead of dividing by mistake.

Answer 6

so 3/2 is one solution so what would the second solution be

Answer 7

b = 3/2 , b= 8/3

Answer 8

Try to solve the other equation we had earlier:
3b - 8 = 0

Answer 9

ok

Answer 10

3z^2+12z=0 one solution would be 0 is that the only solution

Answer 11

yeah