Question

A Piper Cub has an average air speed that is 10mph faster than a Cessna 150 airplane. If the combined distance traveled by these two small planes is 690 miles after 3 hr, what is the average speed of each plane?

Answer 1

let x be speed 1, y be speed 2. 3(x+y) = 690. x = y + 10.

So Y=110
X= 120

is this correct?

Answer 2

v1 = 10 + v2

Answer 3

so I'm wrong?

Answer 4

well im doing it differently

Answer 5

do you agree that v1 = 10 + v2

Answer 6

v1 is the speed of the piper cub

Answer 7

yes

Answer 8

ok the distance we know is d = v* t , where v is the speed or rate, like d = rt

Answer 9

right

Answer 10

so the total distance you add the distances of the two planes ,
so v1*3 + (10+v2) *3 = 690

Answer 11

so you have a system of equations ,

Answer 12

since you know that v1 = 10 + v2, you can substitute that into the second equation

Answer 13

ok

Answer 14

(10 + v2) *3 + (10+v2)*3 = 690

Answer 15

maybe someone should check my work

Answer 16

\[\sqrt{105}\]

Answer 17

v =10.25695

Answer 18

i got v2 = 105

Answer 19

as did I

Answer 20

so v1 = 115

Answer 21

hmm, so The first one I did was wrong

Answer 22

no no nio

Answer 23

i made a mistake

Answer 24

we had v1 *3 + v2 *3 = 690

Answer 25

3 ( v1 +v2 ) = 690

Answer 26

substitute v1 = 10 + v2

Answer 27

3 ( 10 + v2 + v2) = 690

Answer 28

so v2 = 110

Answer 29

so v1 = 100

Answer 30

i meant

Answer 31

oh, I got 120, let me check my math

Answer 32

v1 = 120

Answer 33

you did everything right

Answer 34

AWESOME! thank you sooo much!