Question

how do you find the inverse of y=x^2 +2

Answer 1

get x by itself
y-2 = x^2
sqrt(y-2) = x

Answer 2

i thought you had to switch x and y. so you would have x=y^2 +2 then you subtract 2 so its x-2=y^2

Answer 3

either way works
you will still get f^-1 = sqrt(x-2)

Answer 4

so the answer is ?

Answer 5

y= sqrt of x-2?

Answer 6

correct

Answer 7

thank you. can you help me some more.?

Answer 8

what do you have

Answer 9

the direcxtions say find ^-1 and the doman and range of f (-1) determine where f^-1 is a function. and the problem is
f(x) sqrt 3x

Answer 10

ok flip x and y
x = sqrt(3y)
solve for y

Answer 11

so the anser is x^2 = y

Answer 12

dont forget about the 3
x^2 = 3y
(x^2/3) = y
now what is domain and range

Answer 13

domain is all real. and range idk

Answer 14

good
range is all possible y-values
since x is squared, all the negative x's we put in become positive right?
so our y value is always positive

Answer 15

ohh. so its y is greater than 0
?

Answer 16

correct, well equal to
y>=0

Answer 17

oh em gee thank you.
:]

Answer 18

your welcome