Find the length of the curve y=((x^6)+8)/16x^2) from x=2 to x=3

Question

anonymous · Answer

Have you ever heard about arc length?

anonymous · Answer

yes

anonymous · Answer

Tell us more, what is the formula?

anonymous · Answer

arc length=$$\int\limits_{a}^{b}1+(dy/dx)^2$$

anonymous · Answer

You're brilliant. What is the derivative of$$(x ^{6}+8)/(16x ^{2})$$

anonymous · Answer

$$(64x^7+256)/(256x^4)$$

anonymous · Answer

its easy lol , why did u ask

anonymous · Answer

OK Ramo, one more time pull up the arc length formula and stick this number the derivative where you see dy/dx

anonymous · Answer

alright after i plug it into the formula to get $$\int\limits_{2}^{3}1+((64x^7+256)/(256x^4)^2dx$$

anonymous · Answer

Like my tutor like to say: "You have to clean it up." The square goes through the top and the bottom. The bottom is easy, just plug 256 in calculator and square it. (x^4)^2 just multiply 2x4. The top is, oh well, back to college algebra, sum of two squares.

anonymous · Answer

awesome thanks so much :)

anonymous · Answer

Might be a mistake in the numerator. Show us again where you went from original problem to derivative.