Find the length of the curve y=((x^6)+8)/16x^2) from x=2 to x=3
Have you ever heard about arc length?
yes
Tell us more, what is the formula?
arc length=\[\int\limits_{a}^{b}1+(dy/dx)^2\]
You're brilliant. What is the derivative of\[(x ^{6}+8)/(16x ^{2})\]
\[(64x^7+256)/(256x^4)\]
its easy lol , why did u ask
OK Ramo, one more time pull up the arc length formula and stick this number the derivative where you see dy/dx
alright after i plug it into the formula to get \[\int\limits_{2}^{3}1+((64x^7+256)/(256x^4)^2dx\]
Like my tutor like to say: "You have to clean it up." The square goes through the top and the bottom. The bottom is easy, just plug 256 in calculator and square it. (x^4)^2 just multiply 2x4. The top is, oh well, back to college algebra, sum of two squares.
awesome thanks so much :)
Might be a mistake in the numerator. Show us again where you went from original problem to derivative.
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