Question

can some one help me find the the local extrema for 2x^5-5x^2+1

Answer 1

take the derivative and find the zeros

Answer 2

D(2x^5 -5x^2 +1) = 10x^4 -10x

10x^4 = 10x

x^4 = x ...... mu guess is at 1 and -1

Answer 3

x(x^3 - 1)

(10)(x)(x-1)(x^2 +x +1) or quite possibly at:

x = 0, 1

Answer 4

check 2nd derivative for concavity...

Answer 5

or plug these x value sinto the original and see whats bigger :)

Answer 6

f(0) = 1

f(1) = -2

Answer 7

http://www.wolframalpha.com/input/?i=2x%5E5-5x%5E2%2B1 gives you a good picture of it

Answer 8

awesome thank you very much