Question

integral of 1/square root of 16+4x-2x^2 times dx
This is a calc 2 question think its trig substitution helppppp

Answer 1

\[\int\limits_{}^{}1/\sqrt{16+4x-2x^2}\]

Answer 2

http://www3.wolframalpha.com/Calculate/MSP/MSP32219fa64agc0742gi500001ee9bc7e7adge57i?MSPStoreType=image/gif&s=18&w=462&h=533

Answer 3

i made the bottom as \[\sqrt{-2(x-1)^2+1}\] then u=x-1 so gotta be \[\int\limits_{}^{}1/\sqrt{18-2u^2}\]

Answer 4

oh god thanx prony

Answer 5

*rony

Answer 6

np =)