Question

Find the vector v, and its magnitude is 5. v is orthogonal to x axis, and the dot product v.w = 6, and the vector w=i+2j.

Answer 1

v.w=|v||w|cos theta

Answer 2

a vetor that is perpendicular to the x axis with a magnitude of 5 is <0,5>

Answer 3

is this vector in R^3?

Answer 4

does v have ai+bj form
or
does v have ai+bj+ck form?

Answer 5

2 dimensions or 3?

Answer 6

if w=<1,2>.......

v.w = (1.0)+(5.2) = 10...not 6

Answer 7

the question makes no sense...

Answer 8

(1.0)+(2.3) = 6 but then v =<0,3> with a magnitude of 3

Answer 9

the answer is <0,3,4>

Answer 10

the answer is...... clarify the question lol

Answer 11

i got what amistre got

Answer 12

a condradiction

Answer 13

find the real roots of x^2 +9

Answer 14

but i dont understand how he got the number 4 in the answer

Answer 15

oh..by the way; when i say real rots i mean complex lol

Answer 16

ok so we are looking at 3 dimensions not 2

Answer 17

<1,2,0>
<0,3,4>
--------
6...yes

Answer 18

so....<0,3> is what it looks like when staring at it from the xy plane

Answer 19

0^2 +3^2 +z^2 = |v|^2

Answer 20

9+z^2 = 5^2

z^2 = 25 - 6

z = sqrt(16) = 4

Answer 21

-6 means -9 :)

Answer 22

thats what I did :)

Answer 23

lol..its like haveing a parrot :)

Answer 24

hey, may you type in the word and send me?

Answer 25

just copy it off of here and put it in a text editor.. like SWord or notepad

Answer 26

....my shift keys are on the fritz...

Answer 27

Thanks a lot