Question

how do we factor (3n-2)^2 ÷ 3^n

Answer 1

exapnd it out

Answer 2

\[{(3n-2)^{2} \over 3^{n}} \]\[{(9n^{2} - 12n +4) \over (3^{n})} \]
that's all i can get.. is that what it is ?

Answer 3

3n^2 -12n +4
------------- you sure you typed it right?
3^n

Answer 4

9n^2...doh!

Answer 5

hehe it happens lol

Answer 6

we can try taking the log of this stuff if so

Answer 7

umm...why did we expand to get factors :) seems backwards eh

Answer 8

don't you need an equal to log it out ?

Answer 9

thank you MathMind and amistre64, helpfull indeed