Question

can some one check this

Answer 1

\[f(x)=x^2+5x+1 \]put into the differance quo =2x+5+h

Answer 2

yes.
\[\frac{f(x+h)-f(x)}{h}=\frac{(x+h)^2+5(x+h)+1-(x^2+5x+1)}{h}\]
\[\frac{x^2+2xh+h^2+5x+5h+1-x^2-5x-1}{h}\]
\[\frac{2xh+5h+h^2}{h}\]
\[2x+5+h\]