Question

A vertical parabola has vertex (4,1) and Y intercept 5. What are its X intercepts?

Answer 1

y= A(x-4)^2 + 1 is the general form of such a parabola

Answer 2

we know that when x=0, y= 5

Answer 3

so we can find A

Answer 4

5 = 16A +1

A= (1/4)

Answer 5

so y= (1/4) (x-4)^2 + 1 x intercepts, set y=0

Answer 6

(x-4)^2 = -4 , this has no solution! , no x intercepts

Answer 7

Thank you

Answer 8

how did you get -4?