Question

complete the following integral or partial substitution with
x tanx dx

Answer 1

use integration by parts
u = x dv = tanx
du =dx v = -ln|cosx|

Answer 2

wait nevermind that wont work
i dont know if this has a simple anti-derivative

Answer 3

Do integration by parts,

Take the derivative of x and integral of tanx

=\[x \log|secx| - \int\limits_{}{}tanx\]
=log|secs|(x-1)

Answer 4

That should be secx*

Answer 5

Sorry did a mistake, its not that simple, will think on it!

Answer 6

= uv - integral v du

so now all thats left is finding integral of ln(secx)

Answer 7

let u= sec(x) , du = sec(x)tan(x) dx --> dx = du/ sec(x)tan(x)

Answer 8

so integral ln(u) du / sec(x) tan(x) = \[\frac{ \ln(u) du }{u \sqrt{u^2-1}} \]

Answer 9

yes , hmm, I dont think you can go anywhere there