Question

if \[\log_{\sin x}\cos x-1+\log_{\sin x}\sin 2x \] then the values of x are

Answer 1

i assume that + means =
then
cot x = sin2x
sinx = +1/root2 , -1/root2

Answer 2

oh crap!
\[\log_{\sin x}\cos x=1+\log_{\sin x}\sin 2x\] this is the Q

Answer 3

although it doesnt differ much from what you assumed=)

Answer 4

did u get it now??

Answer 5

how did you simplify the log terms bro??

Answer 6

write 1 as log(sinx) to base sinx

Answer 7

then bring it to the other side..it becomes log(cotx) to base sinx

Answer 8

ok got it..no need to xplain nemore buddy=)

Answer 9

thnx